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Let's say we have a function f(x)=3x^4+2x+7 and want to find the tangent at x=1 Step One: Find the y-coordinate by plugging in x f(x)=81+2+7=90 Step Two: Find the derivative of the function f(x)=3x^4+2x+7 - f'(x)=12x^3+2 Step Three: Plug the point values in f'(x)-90=1728(x-1)+2 Step Four: Take it out of point slope form if you so please f'(x)=1728(x-1)+92

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